JEE Advance - Physics (2013 - Paper 2 Offline - No. 14)
The magnitude of the induced electric field in the orbit at any instant of time during the time interval of the magnetic field change is
$${{BR} \over 4}$$
$${{BR} \over 2}$$
BR
2BR
Explanation
Let the point charge Q is moving in a circle of constant radius R in anticlockwise direction as shown in the figure.
The magnetic flux through the circular loop at time t is given by $$\phi = B(\overrightarrow t )\,.\,(\pi {R^2}\widehat z)\, = \pi B(t){R^2}$$. Faraday's law gives the induced emf e as
$$e = - {{d\phi } \over {dt}} = - \pi {R^2}{{dB(t)} \over {dt}} = - \pi {R^2}B$$ ..... (1)
Lenz's law gives the direction of induced current and hence electric field $$(\overrightarrow E )$$ as clockwise. The induced emf is related to $$\overrightarrow E $$ by
$$e = \oint {\overrightarrow E .\,d\overrightarrow l = - E(2\pi R)} $$ ..... (2)
Eliminate e from equations (1) and (2) to get E = BR/2.
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