JEE Advance - Physics (2013 - Paper 1 Offline - No. 19)
The work functions of silver and sodium are 4.6 and 2.3 eV, respectively. The ratio of the slope of the stopping potential versus frequency plot for silver to that of sodium is ___________.
Answer
1
Explanation
We have,
$$V = {{hf} \over e} - {\phi \over e}$$
Slope is h/e.
Slope is the same for both silver and sodium.
Therefore, the ratio of the slope of the stopping potential versus frequency plot for silver to that of sodium is 1 : 1.
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