JEE Advance - Physics (2012 - Paper 2 Offline - No. 15)
What is the maximum energy of the anti-neutrino?
Zero.
Much less than 0.8 $$\times$$ 106 eV.
Nearly 0.8 $$\times$$ 106 eV.
much larger than 0.8 $$\times$$ 106 eV.
Explanation
$${K_p} + {K_{\overline e }} + {K_{\overline v }}$$ = 0.8 $$\times$$ 106 eV
When electron has zero kinetic energy is shared by antineutrino and proton.
Then, $${K_p} + {K_{\overline v }}$$ = 0.8 $$\times$$ 106 eV
As antineutrino is very light mass in comparison to proton so it will have almost contribution in total energy.
$$\therefore$$ Its energy is almost 0.8 $$\times$$ 106 eV
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