JEE Advance - Physics (2009 - Paper 2 Offline - No. 19)

Three objects A, B and C are kept in a straight line on a frictionless horizontal surface. These have masses m, 2m and m, respectively. The object A moves towards B with a speed 9 m/s and makes an elastic collision with it. Thereafter, B makes completely inelastic collision with C. All motions occur on the same straight line. Find the final speed (in m/s) of the object C.
Answer
4

Explanation

Let $$V_1$$ and $$V_2$$ be the velocities of blocks A and B immediately after the elastic collision:

$${v_1} = \left( {{{{m_1} - {m_2}} \over {{m_1} + {m_2}}}} \right)m = \left( {{{m - 2m} \over {m + 2m}}} \right) \times 9 = - 3$$ m/s

$${v_2} = \left( {{{2{m_1}} \over {{m_1} + {m_2}}}} \right)m = \left( {{{2m} \over {m + 2m}}} \right) \times 9 = 6$$ m/s

IIT-JEE 2009 Paper 2 Offline Physics - Work Power & Energy Question 4 English Explanation

After the perfectly inelastic collision between blocks B and C, let $$v$$ be the common velocity. Applying centre of mass concept, we get

$$2m{v_2} = (2m + m)v$$

$$ \Rightarrow v = {2 \over 3} \times 6 = 4$$ m/s

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