JEE Advance - Physics (2007 - Paper 2 Offline - No. 20)
Column I describe some situations in which a small object moves. Column II describes some characteristics of these motions. Match the situation in Column I with the characteristics in Column II and indicate your answer by darkening appropriate bubbles in the $$4 \times 4$$ matrix given in the ORS.
Column I | Column II | ||
---|---|---|---|
(A) | The object moves on the x-axis under a conservative force in such a way that its "speed" and "position" satisfy $$v = {c_1}\sqrt {{c_2} - {x^2}} $$, where $$c_1$$ and $$c_2$$ are positive constants. | (P) | The object executes a simple harmonic motion. |
(B) | The object moves on the x-axis in such a way that its velocity and its displacement from the origin satisfy $$v=-kx$$, where $$k$$ is a positive constant. | (Q) | The object does not change its direction. |
(C) | The object is attached to one end of a massless spring of a given spring constant. The other end of the spring is attached to the ceiling of an elevator. Initially everything is at rest. The elevator starts going upwards with a constant acceleration a. The motion of the object is observed from the elevator during the period it maintains this acceleration. | (R) | The kinetic energy of the object keeps on decreasing |
(D) | The object is projected from the earth's surface vertically upwards with a speed $$2\sqrt {GMe/{\mathop{\rm Re}\nolimits} } $$, where, M$$_e$$ is the mass of the earth and R$$_e$$ is the radius of the earth. Neglect forces from objects other than the earth. | (S) | The object can change its direction only once. |
Explanation
Reason:
In above figure shown that S.H.M
Therefore, $$f_s=Kx$$
Given, $$v = {c_1}\sqrt {{c_2} - {x^2}} $$ ..... (i)
For a simple harmonic motion,
$$v = \omega \sqrt {{A^2} - {x^2}} $$ ..... (ii)
On comparing eq. (i) & (ii) therefore it shows the S.H.M of particle.
A $$\to$$ P
(b) Given,
$$v=-kx$$
At $$x=0,v=0$$
$$x=2,v=-2k$$
$$x=-5,v=+5k$$
The above consideration show that particle is coming from minus x-axis.
Velocity is decreasing with time.
Graph:
Therefore, no change in direction, velocity keeps on decreasing. So that kinetic energy is decreasing with time.
B $$\to q_1r$$
(C) From the reference frame of the observer in the elevator a constant force acts on the object. Hence the motion of the object will remain simple harmonic.
Therefore, option 1 is correct.
Velocity of object
$$v = 2\sqrt {G{{{M_e}} \over {{R_e}}}} = \sqrt 2 \sqrt {2G{{{M_e}} \over {{R_e}}}} = \sqrt 2 {v_e}$$
Since, $$v > {v_e}$$ (where $$v_e$$ is escape velocity) object will move out of earth.
Hence, option (Q) and (R) are correct.
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