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JEE Advance - Physics (2007 - Paper 2 Offline - No. 18)

The figure shows surface XY separating two transparent media, medium -1 and medium -2 . The lines ab and cd represent wavefronts of a light wave traveling in medium -1 and incident on X Y. The lines ef and gh represent wavefronts of the light wave in medium -2 after refraction.

The figure shows surface XY separating two transparent media, medium -1 and medium -2 . The lines ab and cd represent wavefronts of a light wave traveling in medium -1 and incident on X Y. The lines ef and gh represent wavefronts of the light wave in medium -2 after refraction.

The figure shows surface XY separating two transparent media, medium -1 and medium -2 . The lines ab and cd represent wavefronts of a light wave traveling in medium -1 and incident on X Y. The lines ef and gh represent wavefronts of the light wave in medium -2 after refraction.

The phases of the light wave at $$c, d, e$$ and $$f$$ are $$\phi_c, \phi_d, \phi_{e}$$ and $$\phi_{f}$$ respectively.

It is given that $$\phi_{c} \neq \phi_{f}$$.

$$\phi_{c}$$ cannot be equal to $$\phi_{d}$$
$$\phi_{d}$$ can be equal to $$\phi_{c}$$
$$\left(\phi_{d}-\phi_{f}\right)$$ is equal to $$\left(\phi_{c}-\phi_{e}\right)$$
$$\left(\phi_{d}-\phi_{c}\right)$$ is not equal to $$\left(\phi_{f}-\phi_{e}\right)$$

Explanation

Since point c and d are on same wave front.

Therefore, $$\phi_d=\phi_c$$

Similarly, $$\phi_e=\phi_f$$

$$\therefore~\phi_d-\phi_f=\phi_c-\phi_f$$

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