JEE Advance - Physics (1986 - No. 3)

A simple pendulum of length L and mass (bob) M is oscillating in a plane about a vertical line between angular limit $$ - \phi $$ and $$ + \phi $$. For an angular displacement $$\theta $$ $$\left( {\left| \theta \right| < \phi } \right)$$, the tension in the string and the velocity of the bob are T and V respectively. The following relations hold good under the above conditions:
$$T\cos \theta = Mg$$
$$T - Mg\cos \theta = {{M{V^2}} \over L}$$
The magnitude of the tangential acceleration of the bob $$\left| {{a_T}} \right| = g\sin \theta $$
$$T = Mg\cos \theta $$

Comments (0)

Advertisement