JEE Advance - Physics (1979 - No. 1)
The dispalcement x of particle moving in one direction, under the action of a constant force is related to the time t by the equation $$t = \sqrt x + 3$$
where x is in meters and t in seconds. Find
where x is in meters and t in seconds. Find
(i) The displacement of the particle when its velocity is zero, and
(ii) The work done by the force in the first 6 seconds.
Displacement is 0m when velocity is zero, and work done in the first 6 seconds is 0J
Displacement is 9m when velocity is zero, and work done in the first 6 seconds is 18J
Displacement is 0m when velocity is zero, and work done in the first 6 seconds is 36J
Displacement is -9m when velocity is zero, and work done in the first 6 seconds is -18J
Displacement is -9m when velocity is zero, and work done in the first 6 seconds is 0J
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