JEE Advance - Mathematics (2025 - Paper 1 Online - No. 14)
Consider the following frequency distribution:
| Value | 4 | 5 | 8 | 9 | 6 | 12 | 11 |
|---|---|---|---|---|---|---|---|
| Frequency | 5 | $f_1$ | $f_2$ | 2 | 1 | 1 | 3 |
Suppose that the sum of the frequencies is 19 and the median of this frequency distribution is 6.
For the given frequency distribution, let $\alpha$ denote the mean deviation about the mean, $\beta$ denote the mean deviation about the median, and $\sigma^2$ denote the variance.
Match each entry in List-I to the correct entry in List-II and choose the correct option.
| List – I | List – II |
|---|---|
| (P) 7 f1 + 9 f2 is equal to | (1) 146 |
| (Q) 19 α is equal to | (2) 47 |
| (R) 19 β is equal to | (3) 48 |
| (S) 19 σ2 is equal to | (4) 145 |
| (5) 55 |
(P) → (5) (Q) → (3) (R) → (2) (S) → (4)
(P) → (5) (Q) → (2) (R) → (3) (S) → (1)
(P) → (5) (Q) → (3) (R) → (2) (S) → (1)
(P) → (3) (Q) → (2) (R) → (5) (S) → (4)
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