JEE Advance - Mathematics (2023 - Paper 2 Online - No. 10)
Let $X$ be the set of all five digit numbers formed using 1,2,2,2,4,4,0. For example, 22240 is in $X$ while 02244 and 44422 are not in $X$. Suppose that each element of $X$ has an equal chance of being chosen. Let $p$ be the conditional probability that an element chosen at random is a multiple of 20 given that it is a multiple of 5 . Then the value of $38 p$ is equal to :
Answer
31
Explanation
Number of elements in $\mathrm{X}$ which are multiple of 5
Among these 38 elements, let us calculate when element is not divisible by 20
$\therefore p=\frac{38-7}{38} $
$ \therefore 38 p=31$
Among these 38 elements, let us calculate when element is not divisible by 20
$\therefore p=\frac{38-7}{38} $
$ \therefore 38 p=31$
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