$$\bullet$$ Probability of wining of T₁ against T₂ = 1/2.

$$\bullet$$ Probability of drawing of T₁ against T₂ is = 1/6.

$$\bullet$$ Probability of losing of T₁ against T₂ is = 1/3.

$$\bullet$$ 3 points for win.

$$\bullet$$ 1 point for draw.

$$\bullet$$ 0 point for loss.

P[X = Y] = P(draw) . P(draw) + P(T₁ win) P(T₂ win) + P(T₂ win) . P(T₁ win)

= (1/6 $$\times$$ 1/6) + (1/2 $$\times$$ 1/3) + (1/3 $$\times$$ 1/2) = 13/36