JEE Advance - Mathematics (2013 - Paper 1 Offline - No. 4)

The number of points in $$\left( { - \infty \,\infty } \right),$$ for which $${x^2} - x\sin x - \cos x = 0,$$ is
6
4
2
0

Explanation

$$\text { We know the graph of } y=x \sin x \text { is }$$

JEE Advanced 2013 Paper 1 Offline Mathematics - Trigonometric Functions & Equations Question 37 English Explanation 1

And the graph of $$y=\cos x$$ is

JEE Advanced 2013 Paper 1 Offline Mathematics - Trigonometric Functions & Equations Question 37 English Explanation 2

Now add the graph of $$y=x \sin x$$ and $$y=\cos x$$ and also draw the graph of $$y=x^2$$

JEE Advanced 2013 Paper 1 Offline Mathematics - Trigonometric Functions & Equations Question 37 English Explanation 3

It is clear that the graph of $$y=x^2$$ and $$y=x \sin x +\cos x$$ intersect at two points

$$\therefore$$ The equation $$x^2=x \sin x+x$$ satisfy for two values of $$x$$.

Hints:

(i) Recall the graph of $$y=x \sin x, y=\cos x$$ and $$y=x^2$$.

(ii) Recall the method of addition of two graphs.

(iii) The number of point of intersection of graphs of $$y=f(x)$$ and $$y=g(x)$$ is equal to the number of solution of $$f(x)=g(x)$$

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