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JEE Advance - Mathematics (2009 - Paper 1 Offline - No. 7)

A fair die is tossed repeatedly until a six is obtained. Let X denote the number of tosses required.
A fair die is tossed repeatedly until a six is obtained. Let X denote the number of tosses required.
A fair die is tossed repeatedly until a six is obtained. Let X denote the number of tosses required.
The probability that X = 3 equals
$${{25} \over {216}}$$
$${{25} \over {36}}$$
$${{5} \over {36}}$$
$${{125} \over {216}}$$

Explanation

The required probability is $$P(X = 3)$$

$$\left( {{5 \over 6}} \right)\left( {{5 \over 6}} \right){1 \over 6} = {{25} \over {216}}$$

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