JEE Advance - Mathematics (2009 - Paper 1 Offline - No. 2)
Let $$z = x + iy$$ be a complex number where x and y are integers. Then the area of the rectangle whose vertices are the roots of the equation $$\overline z {z^3} + z{\overline z ^3} = 350$$ is
48
32
40
80
Explanation
We have
$$\overline z {z^3} + z{\overline z ^3} = 350$$
Substituting $$z = x + iy$$, we get
$$({x^2} + {y^2})({x^2} - {y^2}) = 175$$
$$({x^2} + {y^2})({x^2} - {y^2}) = 5 \times 5 \times 7$$
$${x^2} + {y^2} = 25$$
$${x^2} - {y^2} = 7$$
whose solutions are $$x = \pm 4$$ and $$y = \pm 3;x,y \in I$$.
Therefore, that is, area is found as $$8 \times 6 = 48$$ sq. unit.
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