JEE Advance - Mathematics (2008 - Paper 1 Offline - No. 12)
Let z be any point $$A \cap B \cap C$$ and let w be any point satisfying $$\left| {w - 2 - i} \right| < 3\,$$. Then, $$\left| z \right| - \left| w \right| + 3$$ lies between :
- 6 and 3
- 3 and 6
- 6 and 6
- 3 and 9
Explanation
Since, $$|w - (2 + i)| < 3$$
$$|w| - |2 + i| < 3$$
$$ - 3 + \sqrt 5 < |w| < 3 + \sqrt 5 $$
$$ - 3 - \sqrt 5 < |w| < 3 - \sqrt 5 $$
Also, $$|z - (2 + i)| = 3$$
$$ - 3 + \sqrt 5 \le |z| \le 3 + \sqrt 5 $$
$$\therefore$$ $$ - 3 < |z| - |w| + 3 < 9$$
Comments (0)
