JEE Advance - Mathematics (2006 - No. 1)
The values of $$\theta \in \left( {0,2\pi } \right)$$ for which $$2\,{\sin ^2}\theta - 5\,\sin \theta + 2 > 0,$$ are
$$\left( {0,{\pi \over 6}} \right)\, \cup \,\left( {{{5\pi } \over 6},2\pi } \right)$$
$$\,\left( {{\pi \over 8},{{5\pi } \over 6}} \right)$$
$$\left( {0,{\pi \over 8}} \right)\, \cup \,\left( {{\pi \over 6},{{5\pi } \over 6}} \right)$$ v
$$\,\left( {{{41\pi } \over {48}},\,\pi } \right)$$
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