JEE Advance - Mathematics (2004 - No. 23)
If one root is square of the other root of the equation $${x^2} + px + q = 0$$, then the realation between $$p$$ and $$q$$ is
$${p^3} - q\left( {3p - 1} \right) + {q^2} = 0$$
$${p^3} - q\left( {3p + 1} \right) + {q^2} = 0$$
$${p^3} + q\left( {3p - 1} \right) + {q^2} = 0$$
$${p^3} + q\left( {3p + 1} \right) + {q^2} = 0$$
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