JEE Advance - Mathematics (2003 - No. 19)
Coefficient of $${t^{24}}$$ in $${\left( {1 + {t^2}} \right)^{12}}\left( {1 + {t^{12}}} \right)\left( {1 + {t^{24}}} \right)$$ is
$${}^{12}{C_6} + 3$$
$${}^{12}{C_6} + 1$$
$${}^{12}{C_6}$$
$${}^{12}{C_6} + 2$$
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