JEE Advance - Mathematics (2003 - No. 13)
The focal chord to $${y^2} = 16x$$ is tangent to $${\left( {x - 6} \right)^2} + {y^2} = 2,$$ then the possible values of the slope of the chord, are
$$\left\{ { - 1,\,1} \right\}$$
$$\left\{ { - 2,\,2} \right\}$$
$$\left\{ { - 2,\,-1/2} \right\}$$
$$\left\{ { 2,\,-1/2} \right\}$$
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