JEE Advance - Mathematics (2003 - No. 11)
In $$\left[ {0,1} \right]$$ Languages Mean Value theorem is NOT applicable to
$$f\left( x \right) = \left\{ {\matrix{
{{1 \over 2} - x} & {x < {1 \over 2}} \cr
{{{\left( {{1 \over 2} - x} \right)}^2}} & {x \ge {1 \over 2}} \cr
} } \right.$$
$$f\left( x \right) = \left\{ {\matrix{
{\sin x,} & {x \ne 0} \cr
{1,} & {x = 0} \cr
} } \right.$$
$$f\left( x \right) = x\left| x \right|$$
$$f\left( x \right) = \left| x \right|$$
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