JEE Advance - Mathematics (2002 - No. 13) | ExamPlay

JEE Advance - Mathematics (2002 - No. 13)

The equation of the common tangent to the curves $${y^2} = 8x$$ and $$xy = - 1$$ is

$$3y = 9x + 2$$

$$y = 2x + 1$$

$$2y = x + 8$$

$$y= x + 2$$

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