JEE Advance - Mathematics (2000 - No. 23)
The triangle PQR is inscribed in the circle $${x^2}\, + \,\,{y^2} = \,25$$. If Q and R have co-ordinates (3, 4) and ( - 4, 3) respectively, then $$\angle \,Q\,P\,R$$ is equal to
$${\pi \over 2}$$
$${\pi \over 3}$$
$${\pi \over 4}$$
$${\pi \over 6}$$
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