JEE Advance - Mathematics (1999 - No. 32)
If $$x$$ $$=$$ $$9$$ is the chord of contact of the hyperbola $${x^2} - {y^2} = 9,$$ then the equation of the vcorresponding pair of tangents is
$$9{x^2} - 8{y^2} + 18x - 9 = 0$$
$$9{x^2} - 8{y^2} - 18x + 9 = 0$$
$$9{x^2} - 8{y^2} - 18x - 9 = 0$$
$$9{x^2} - 8{y^2} + 18x + 9 = 0$$
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