JEE Advance - Mathematics (1999 - No. 30)
If $$(h, k)$$ is the point of intersection of the normals at $$P$$ and $$Q$$, then $$k$$ is equal to
$${{{a^2} + {b^2}} \over a}$$
$$ - \left( {{{{a^2} + {b^2}} \over a}} \right)$$
$${{{a^2} + {b^2}} \over b}$$
$$ - \left( {{{{a^2} + {b^2}} \over b}} \right)$$
Comments (0)
