JEE Advance - Mathematics (1997 - No. 8)

Let $${z_1}$$ and $${z_2}$$ be roots of the equation $${z^2} + pz + q = 0\,$$ , where the coefficients p and q may be complex numbers. Let A and B represent $${z_1}$$ and $${z_2}$$ in the complex plane. If $$\angle AOB = \alpha \ne 0\,$$ and OA = OB, where O is the origin, prove that $${p^2} = 4q\,{\cos ^2}\left( {{\alpha \over 2}} \right)$$.
$$p^2 = 4q \sin^2(\alpha/2)$$
$$p^2 = 4q \cos^2(\alpha/2)$$
$$p^2 = 2q \cos^2(\alpha)$$
$$p^2 = q \cos^2(\alpha/2)$$
$$p^2 = 4q \tan^2(\alpha/2)$$

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