JEE Advance - Mathematics (1996 - No. 8)
The position vectors of the vertices $$A, B$$ and $$C$$ of a tetrahedron $$ABCD$$ are $$\widehat i + \widehat j + \widehat k,\,\widehat i$$ and $$3\widehat i\,,$$ respectively. The altitude from vertex $$D$$ to the opposite face $$ABC$$ meets the median line through $$A$$ of the triangle $$ABC$$ at a point $$E.$$ If the length of the side $$AD$$ is $$4$$ and the volume of the tetrahedron is $${{2\sqrt 2 } \over 3},$$ find the position vector of the point $$E$$ for all its possible positions.
$$\hat i + \hat j + \hat k$$
$$2\hat i + \hat j + \hat k$$
$$-\hat i + 3\hat j + 3\hat k$$
$$4\hat i + \hat j + \hat k$$
$$-2\hat i + \hat j - \hat k$$
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