JEE Advance - Mathematics (1996 - No. 5)
In how many ways three girls and nine boys can be seated in two vans, each having numbered seats, $$3$$ in the front and $$4$$ at the back? How many seating arrangements are possible if $$3$$ girls should sit together in a back row on adjacent seats? Now, if all the seating arrangements are equally likely, what is the probability of $$3$$ girls sitting together in a back row on adjacent seats?
The total number of seating arrangements is $$7 \times 13!$$, the number of seating arrangements with the three girls sitting together in the back row on adjacent seats is $$12!$$ and the probability is $$1/9!$$.
The total number of seating arrangements is $$13!$$, the number of seating arrangements with the three girls sitting together in the back row on adjacent seats is $$12!$$ and the probability is $$1/9!$$.
The total number of seating arrangements is $$7 \times 13!$$, the number of seating arrangements with the three girls sitting together in the back row on adjacent seats is $$12!$$ and the probability is $$9!$$.
The total number of seating arrangements is $$7 \times 13!$$, the number of seating arrangements with the three girls sitting together in the back row on adjacent seats is $$11!$$ and the probability is $$1/9!$$.
The total number of seating arrangements is $$7 \times 13!$$, the number of seating arrangements with the three girls sitting together in the back row on adjacent seats is $$12!$$ and the probability is $$1/8!$$.
Comments (0)
