JEE Advance - Mathematics (1994 - No. 43)

In a triangle $$ABC$$, $$AD$$ is the altitude from $$A$$. Given $$b>c$$, $$\angle C = {23^ \circ }$$ and $$AD = {{abc} \over {{b^2} - {c^2}}}$$ then $$\angle B = $$.................
23°
67°
113°
46°
90°

Comments (0)

Advertisement