JEE Advance - Mathematics (1994 - No. 33)
The curve $$y = a{x^3} + b{x^2} + cx + 5$$, touches the $$x$$-axis at $$P(-2, 0)$$ and cuts the $$y$$ axis at a point $$Q$$, where its gradient is $$3$$. Find $$a, b, c$$.
a = -1/2, b = -3/4, c = 3
a = 1/2, b = 3/4, c = -3
a = -1/4, b = -3/2, c = 6
a = 1/4, b = 3/2, c = -6
a = -1, b = -3, c = 12
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