JEE Advance - Mathematics (1994 - No. 20)
Let $$2{\sin ^2}x + 3\sin x - 2 > 0$$ and $${x^2} - x - 2 < 0$$ ($$x$$ is measured in radians). Then $$x$$ lies in the interval
$$\left( {{\pi \over 6},\,{{5\pi } \over 6}} \right)\,\,$$
$$\left( { - 1,\,{{5\pi } \over 6}} \right)$$
$$\left( { - 1,\,2} \right)\,\,\,$$
$$\left( {{\pi \over 6},\,2} \right)$$
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