JEE Advance - Mathematics (1993 - No. 21)
An observer at $$O$$ notices that the angle of elevation of the top of a tower is $${30^ \circ }$$. The line joining $$O$$ to the base of the tower makes an angle of $${\tan ^{ - 1}}\left( {1/\sqrt 2 } \right)$$ with the North and is inclined Eastwards. The observer travels a distance of $$300$$ meters towards the North to a point A and finds the tower to his East. The angle of elevation of the top of the tower at $$A$$ is $$\phi $$, Find $$\phi $$ and the height of the tower.
$$\phi = {60^\circ }$$, height = $${100\sqrt 3 }$$ m
$$\phi = {30^\circ }$$, height = $$150$$ m
$$\phi = {45^\circ }$$, height = $${150\sqrt 2 }$$ m
$$\phi = {45^\circ }$$, height = $$300$$ m
$$\phi = {60^\circ }$$, height = $${300\sqrt 3 }$$ m
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