JEE Advance - Mathematics (1993 - No. 14)

A line through $$A (-5, -4)$$ meets the line $$x + 3y + 2 = 0,$$ $$2x + y + 4 = 0$$ and $$x - y - 5 = 0$$ at the points $$B, C$$ and $$D$$ respectively. If $${\left( {15/AB} \right)^2} + {\left( {10/AC} \right)^2} = {\left( {6/AD} \right)^2},$$ find the equation of the line.
2x + 3y + 22 = 0
3x + 2y + 22 = 0
2x - 3y + 22 = 0
3x - 2y + 22 = 0
x + y + 9 = 0

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