JEE Advance - Mathematics (1991 - No. 16)
Two circles, each of radius 5 units, touch each other at (1, 2). If the equation of their common tangent is 4x + 3y = 10, find the equation of the circles.
x^2 + y^2 + 6x + 2y - 15 = 0 and x^2 + y^2 - 10x - 10y + 25 = 0
x^2 + y^2 - 6x - 2y - 15 = 0 and x^2 + y^2 + 10x + 10y + 25 = 0
x^2 + y^2 + 6x - 2y - 15 = 0 and x^2 + y^2 - 10x + 10y + 25 = 0
x^2 + y^2 - 6x + 2y - 15 = 0 and x^2 + y^2 + 10x - 10y + 25 = 0
x^2 + y^2 - 6x - 2y + 15 = 0 and x^2 + y^2 + 10x + 10y - 25 = 0
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