JEE Advance - Mathematics (1990 - No. 23)

A vertical tower $$PQ$$ stands at a point $$P$$. Points $$A$$ and $$B$$ are located to the South and East of $$P$$ respectively. $$M$$ is the mid point of $$AB$$. $$PAM$$ is an equilateral triangle; and $$N$$ is the foot of the perpendicular from $$P$$ and $$AB$$. Let $$AN$$$$=20$$ mrtres and the angle of elevation of the top of the tower at $$N$$ is $${\tan ^{ - 1}}\left( 2 \right)$$. Determine the height of the tower and the angles of elevation of the top of the tower at $$A$$ and $$B$$.
Height of the tower: $$40\sqrt{3}$$ meters
Angle of elevation at A: $$60^{\circ}$$
Angle of elevation at B: $$45^{\circ}$$
Angle of elevation at A: $$30^{\circ}$$
Height of the tower: $$20\sqrt{3}$$ meters

Comments (0)

Advertisement