JEE Advance - Mathematics (1990 - No. 18)
A circle touches the line y = x at a point P such that OP = $${4\sqrt 2 \,}$$, where O is the origin. The circle contains the point (- 10, 2) in its interior and the length of its chord on the line x + y = 0 is $${6\sqrt 2 \,}$$. Determine the equation of the circle.
x^2 + y^2 - 18x - 2y + 32 = 0
x^2 + y^2 + 18x - 2y + 32 = 0
x^2 + y^2 - 18x + 2y + 32 = 0
x^2 + y^2 + 18x + 2y + 32 = 0
x^2 + y^2 - 2x - 18y + 32 = 0
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