JEE Advance - Mathematics (1990 - No. 17)
A line cuts the $$x$$-axis at $$A (7, 0)$$ and the $$y$$-axis at $$B (0, -5)$$. A variable line $$PQ$$ is drawn perpendicular to $$AB$$ cutting the $$x$$axis in $$P$$ and they $$Y$$-axis in $$Q$$. If $$AQ$$ and $$BP$$ intersect at $$R$$, find the locus of R.
x^2 + y^2 + 7x - 5y = 0
x^2 + y^2 - 7x + 5y = 0
x^2 - y^2 - 7x + 5y = 0
x^2 + y^2 - 5x + 7y = 0
x^2 + y^2 + 5x - 7y = 0
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