JEE Advance - Mathematics (1988 - No. 28)

A sign -post in the form of an isosceles triangle $$ABC$$ is mounted on a pole of height $$h$$ fixed to the ground. The base $$BC$$ of the triangle is parallel to the ground. A man standing on the ground at a distance $$d$$ from the sign-post finds that the top vertex $$A$$ of the triangle subtends an angle $$\beta $$ and either of the other two vertices subtends the same angle $$\alpha $$ at his feet. Find the area of the triangle.
(d tan β - h)√(h² cot² α - d²)
(d tan β + h)√(h² cot² α + d²)
(d tan β - h)√(h² tan² α - d²)
(d tan α - h)√(h² cot² β - d²)
(d tan β - h)√(h² cot² α + d²)

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