JEE Advance - Mathematics (1986 - No. 3)
From the point A(0, 3) on the circle $${x^2} + 4x + {(y - 3)^2} = 0$$, a chord AB is drawn and extended to a point M such that AM = 2AB. The equation of the locus of M is..........................
x^2 + y^2 + 8x - 6y + 9 = 0
x^2 + y^2 - 8x + 6y + 9 = 0
x^2 + y^2 + 8x + 6y + 9 = 0
x^2 + y^2 - 8x - 6y + 9 = 0
x^2 + y^2 + 4x - 3y + 9 = 0
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