JEE Advance - Mathematics (1986 - No. 18)
The equation of the line passing through the points of intersection of the circles $$3{x^2} + 3{y^2} - 2x + 12y - 9 = 0$$ and $${x^2} + {y^2} - 6x + 2y - 15 = 0$$ is..............................
10x + 3y - 18 = 0
10x - 3y + 18 = 0
10x - 3y - 18 = 0
3x - 10y - 18 = 0
3x + 10y + 18 = 0
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