JEE Advance - Mathematics (1983 - No. 8)
Cards are drawn one by one at random from a well - shuffled full pack of $$52$$ playing cards until $$2$$ aces are obtained for the first time. If $$N$$ is the number of cards required to be drawn, then show that $${P_r}\left\{ {N = n} \right\} = {{\left( {n - 1} \right)\left( {52 - n} \right)\left( {51 - n} \right)} \over {50 \times 49 \times 17 \times 13}}$$ where $$2 \le n \le 50$$
The probability that the nth card is an ace and one of the first n-1 cards is an ace.
The probability that the nth card is an ace and exactly two of the first n-1 cards are aces.
The probability that the nth card is an ace and exactly one of the first n-1 cards is an ace.
The probability that the nth card is not an ace and exactly one of the first n-1 cards is an ace.
The probability that the nth card is an ace.
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