JEE Advance - Mathematics (1983 - No. 55)
The end $$A, B$$ of a straight line segment of constant length $$c$$ slide upon the fixed rectangular axes $$OX, OY$$ respectively. If the rectangle $$OAPB$$ be completed, then show that the locus of the foot of the perpendicular drawn from $$P$$ to $$AB$$ is $${x^{{2 \over 3}}} + {y^{{2 \over 3}}} = {c^{{2 \over 3}}}$$
The locus of the foot of the perpendicular drawn from P to AB is x^(2/3) + y^(2/3) = c^(2/3)
The locus of the foot of the perpendicular drawn from P to AB is x^2 + y^2 = c^2
The locus of the foot of the perpendicular drawn from P to AB is x + y = c
The locus of the foot of the perpendicular drawn from P to AB is x^(3/2) + y^(3/2) = c^(3/2)
The locus of the foot of the perpendicular drawn from P to AB is x^3 + y^3 = c^3
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