JEE Advance - Mathematics (1983 - No. 20)
Given the points $$A\left( {0,4} \right)$$ and $$B\left( {0, - 4} \right)$$, the equation of the locus of the point $$P\left( {x,y} \right)$$ such that $$\left| {AP - BP} \right| = 6$$ is .............
$$ {{{x^2}} over 9} - {{{y^2}} over 7} = 1$$
$$ {{{y^2}} over 9} - {{{x^2}} over 7} = 1$$
$$ {{{x^2}} over 7} - {{{y^2}} over 9} = 1$$
$$ {{{y^2}} over 7} - {{{x^2}} over 9} = 1$$
$$ {{{x^2}} over 16} - {{{y^2}} over 9} = 1$$
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