JEE Advance - Mathematics (1982 - No. 14)

Show that the equation $${e^{\sin x}} - {e^{ - \sin x}} - 4 = 0$$ has no real solution.
The function $$f(x) = e^{\sin x} - e^{-\sin x} - 4$$ is always greater than 0, thus no real solution exists.
The function $$f(x) = e^{\sin x} - e^{-\sin x} - 4$$ is always less than 0, thus no real solution exists.
The function $$f(x) = e^{\sin x} - e^{-\sin x} - 4$$ has a minimum value of -4, thus no real solution exists.
The function $$f(x) = e^{\sin x} - e^{-\sin x} - 4$$ is oscillating between -5 and -3, thus no real solution exists.
The function $$f(x) = e^{\sin x} - e^{-\sin x} - 4$$ is unbounded, thus no real solution exists.

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