JEE Advance - Mathematics (1981 - No. 17)

Find the equations of the circle passing through (- 4, 3) and touching the lines x + y = 2 and x - y = 2.
x^2 + y^2 + 2(10 + \sqrt{54})x + 55 + \sqrt{54} = 0
x^2 + y^2 + 2(10 - \sqrt{54})x + 55 - \sqrt{54} = 0
x^2 + y^2 - 2(10 + \sqrt{54})x - 55 - \sqrt{54} = 0
x^2 + y^2 - 2(10 - \sqrt{54})x - 55 + \sqrt{54} = 0
x^2 + y^2 + 20x + 55 = 0

Comments (0)

Advertisement