Sign In

JEE Advance - Mathematics (1978 - No. 17)

Solve for $$x:{4^x} - {3^{^{x - {1 \over 2}}}}\, = {3^{^{x + {1 \over 2}}}}\, - {2^{2x - 1}}$$
0
1
3/2
2
5/2

Comments (0)

Advertisement