JEE Advance - Mathematics (1978 - No. 1)
Find the derivative of $$\sin \left( {{x^2} + 1} \right)$$ with respect to $$x$$ first principle.
$$cos left( {{x^2} + 1}
ight)$$
$$-2x,cos left( {{x^2} + 1}
ight)$$
$$2x,cos left( {{x^2} + 1}
ight)$$
$$-2x,sin left( {{x^2} + 1}
ight)$$
$$cos(x^2+1) + sin(x^2+1)$$
Comments (0)
