JEE Advance - Mathematics Hindi (2016 - Paper 2 Offline - No. 7)
$$\int\limits_{-{\pi \over 2}}^{{\pi \over 2}} {{{{x^2}\cos x} \over {1 + {e^x}}}dx} $$ का मान बराबर है
$${{{\pi ^2}} \over 4} - 2$$
$${{{\pi ^2}} \over 4} + 2$$
$${\pi ^2} - {e^{{\pi \over 2}}}$$
$${\pi ^2} + {e^{{\pi \over 2}}}$$
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