JEE Advance - Chemistry (2024 - Paper 1 Online - No. 11)
Among $\mathrm{V}(\mathrm{CO})_6, \mathrm{Cr}(\mathrm{CO})_5, \mathrm{Cu}(\mathrm{CO})_3, \mathrm{Mn}(\mathrm{CO})_5, \mathrm{Fe}(\mathrm{CO})_5,\left[\mathrm{Co}(\mathrm{CO})_3\right]^{3-},\left[\mathrm{Cr}(\mathrm{CO})_4\right]^{4-}$, and $\operatorname{Ir}(\mathrm{CO})_3$, the total number of species isoelectronic with $\mathrm{Ni}(\mathrm{CO})_4$ is _________.
[Given, atomic number: $\mathrm{V}=23, \mathrm{Cr}=24, \mathrm{Mn}=25, \mathrm{Fe}=26, \mathrm{Co}=27, \mathrm{Ni}=28, \mathrm{Cu}=29, \mathrm{Ir}=77$ ]
Answer
1
Explanation
$$
\begin{aligned}
&\text { Total number of electron in } \mathrm{Ni}(\mathrm{CO})_4=84\\\\
&\begin{array}{lll}
\text { Species } & & \text { Total electron } \\\\
\mathrm{V}(\mathrm{CO})_6 & - & 107 \\\\
\mathrm{Cr}(\mathrm{CO})_5 & - & 94 \\\\
\mathrm{Cu}(\mathrm{CO})_3 & - & 71 \\\\
\mathrm{Mn}(\mathrm{CO})_5 & - & 95 \\\\
\mathrm{Fe}(\mathrm{CO})_5 & - & 96 \\\\
{\left[\mathrm{Co}(\mathrm{CO})_3\right]^{3-}} & - & 72 \\\\
{\left[\mathrm{Cr}(\mathrm{CO})_4\right]^{4-}} & - & 84 \\\\
\operatorname{Ir}(\mathrm{CO})_3 & - & 119
\end{array}
\end{aligned}
$$
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