JEE Advance - Chemistry (2022 - Paper 2 Online - No. 4)
The reaction of $\mathrm{Xe}$ and $\mathrm{O}_{2}{F}_{2}$ gives a $\mathrm{Xe}$ compound $\mathbf{P}$. The number of moles of $\mathrm{HF}$ produced by the complete hydrolysis of $1 \mathrm{~mol}$ of $\mathbf{P}$ is __________.
Answer
4
Explanation
$$\mathrm{Xe}+2 \mathrm{O}_{2}{F}_{2} \rightarrow \underset{(\mathrm{P})}{\mathrm{XeF}_{4}}+2 \mathrm{O}_{2}$$
$$\underset{(\mathrm{P})}{\mathrm{6XeF}_{4}}+12 \mathrm{H}_{2} \mathrm{O} \longrightarrow 4 \mathrm{Xe}+2 \mathrm{XeO}_{3}+24 \mathrm{HF}+3 \mathrm{O}_{2}$$
So, from the above reaction, it is clear that 6 moles of $\mathrm{XeF}_4$ produces 24 moles of $\mathrm{HF}$.
So, 1 mole of $\mathrm{XeF}_4$ will produce $\frac{24}{6}$ moles of HF, i.e., 4 moles of $\mathrm{HF}$.
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