JEE Advance - Chemistry (2022 - Paper 2 Online - No. 16)
The reaction of $\mathrm{HClO}_{3}$ with $\mathrm{HCl}$ gives a paramagnetic gas, which upon reaction with $\mathrm{O}_{3}$ produces
$\mathrm{Cl}_{2} \mathrm{O}$
$\mathrm{ClO}_{2}$
$\mathrm{Cl}_{2} \mathrm{O}_{6}$
$\mathrm{Cl}_{2} \mathrm{O}_{7}$
Explanation
$\mathrm{HClO}_3$ reacts with $\mathrm{HCl}$ according to the following equation,
$$ 2 \mathrm{HClO}_3+2 \mathrm{HCl} \longrightarrow 2 \mathrm{ClO}_2+\mathrm{Cl}_2+2 \mathrm{H}_2 \mathrm{O} $$
$\mathrm{ClO}_2$ molecule is paramagnetic, as it contains odd number of electrons.
$$ 2 \mathrm{ClO}_2+2 \mathrm{O}_3 \longrightarrow \mathrm{Cl}_2 \mathrm{O}_6+2 \mathrm{O}_2 $$
$$ 2 \mathrm{HClO}_3+2 \mathrm{HCl} \longrightarrow 2 \mathrm{ClO}_2+\mathrm{Cl}_2+2 \mathrm{H}_2 \mathrm{O} $$
$\mathrm{ClO}_2$ molecule is paramagnetic, as it contains odd number of electrons.
$$ 2 \mathrm{ClO}_2+2 \mathrm{O}_3 \longrightarrow \mathrm{Cl}_2 \mathrm{O}_6+2 \mathrm{O}_2 $$
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